Optimal. Leaf size=313 \[ \frac {7 (7 A-17 B+33 C) \sin (c+d x)}{30 a^3 d \sec ^{\frac {3}{2}}(c+d x)}-\frac {(13 A-33 B+63 C) \sin (c+d x)}{6 a^3 d \sqrt {\sec (c+d x)}}-\frac {(13 A-33 B+63 C) \sin (c+d x)}{10 d \sec ^{\frac {5}{2}}(c+d x) \left (a^3 \cos (c+d x)+a^3\right )}-\frac {(13 A-33 B+63 C) \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} F\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{6 a^3 d}+\frac {7 (7 A-17 B+33 C) \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} E\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{10 a^3 d}-\frac {(2 A-7 B+12 C) \sin (c+d x)}{15 a d \sec ^{\frac {7}{2}}(c+d x) (a \cos (c+d x)+a)^2}-\frac {(A-B+C) \sin (c+d x)}{5 d \sec ^{\frac {9}{2}}(c+d x) (a \cos (c+d x)+a)^3} \]
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Rubi [A] time = 0.72, antiderivative size = 313, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 7, integrand size = 43, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.163, Rules used = {4221, 3041, 2977, 2748, 2635, 2641, 2639} \[ \frac {7 (7 A-17 B+33 C) \sin (c+d x)}{30 a^3 d \sec ^{\frac {3}{2}}(c+d x)}-\frac {(13 A-33 B+63 C) \sin (c+d x)}{6 a^3 d \sqrt {\sec (c+d x)}}-\frac {(13 A-33 B+63 C) \sin (c+d x)}{10 d \sec ^{\frac {5}{2}}(c+d x) \left (a^3 \cos (c+d x)+a^3\right )}-\frac {(13 A-33 B+63 C) \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} F\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{6 a^3 d}+\frac {7 (7 A-17 B+33 C) \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)} E\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{10 a^3 d}-\frac {(2 A-7 B+12 C) \sin (c+d x)}{15 a d \sec ^{\frac {7}{2}}(c+d x) (a \cos (c+d x)+a)^2}-\frac {(A-B+C) \sin (c+d x)}{5 d \sec ^{\frac {9}{2}}(c+d x) (a \cos (c+d x)+a)^3} \]
Antiderivative was successfully verified.
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Rule 2635
Rule 2639
Rule 2641
Rule 2748
Rule 2977
Rule 3041
Rule 4221
Rubi steps
\begin {align*} \int \frac {A+B \cos (c+d x)+C \cos ^2(c+d x)}{(a+a \cos (c+d x))^3 \sec ^{\frac {7}{2}}(c+d x)} \, dx &=\left (\sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)}\right ) \int \frac {\cos ^{\frac {7}{2}}(c+d x) \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right )}{(a+a \cos (c+d x))^3} \, dx\\ &=-\frac {(A-B+C) \sin (c+d x)}{5 d (a+a \cos (c+d x))^3 \sec ^{\frac {9}{2}}(c+d x)}+\frac {\left (\sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)}\right ) \int \frac {\cos ^{\frac {7}{2}}(c+d x) \left (\frac {1}{2} a (A+9 B-9 C)+\frac {5}{2} a (A-B+3 C) \cos (c+d x)\right )}{(a+a \cos (c+d x))^2} \, dx}{5 a^2}\\ &=-\frac {(A-B+C) \sin (c+d x)}{5 d (a+a \cos (c+d x))^3 \sec ^{\frac {9}{2}}(c+d x)}-\frac {(2 A-7 B+12 C) \sin (c+d x)}{15 a d (a+a \cos (c+d x))^2 \sec ^{\frac {7}{2}}(c+d x)}+\frac {\left (\sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)}\right ) \int \frac {\cos ^{\frac {5}{2}}(c+d x) \left (-\frac {7}{2} a^2 (2 A-7 B+12 C)+\frac {5}{2} a^2 (5 A-10 B+21 C) \cos (c+d x)\right )}{a+a \cos (c+d x)} \, dx}{15 a^4}\\ &=-\frac {(A-B+C) \sin (c+d x)}{5 d (a+a \cos (c+d x))^3 \sec ^{\frac {9}{2}}(c+d x)}-\frac {(2 A-7 B+12 C) \sin (c+d x)}{15 a d (a+a \cos (c+d x))^2 \sec ^{\frac {7}{2}}(c+d x)}-\frac {(13 A-33 B+63 C) \sin (c+d x)}{10 d \left (a^3+a^3 \cos (c+d x)\right ) \sec ^{\frac {5}{2}}(c+d x)}+\frac {\left (\sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)}\right ) \int \cos ^{\frac {3}{2}}(c+d x) \left (-\frac {15}{4} a^3 (13 A-33 B+63 C)+\frac {35}{4} a^3 (7 A-17 B+33 C) \cos (c+d x)\right ) \, dx}{15 a^6}\\ &=-\frac {(A-B+C) \sin (c+d x)}{5 d (a+a \cos (c+d x))^3 \sec ^{\frac {9}{2}}(c+d x)}-\frac {(2 A-7 B+12 C) \sin (c+d x)}{15 a d (a+a \cos (c+d x))^2 \sec ^{\frac {7}{2}}(c+d x)}-\frac {(13 A-33 B+63 C) \sin (c+d x)}{10 d \left (a^3+a^3 \cos (c+d x)\right ) \sec ^{\frac {5}{2}}(c+d x)}+\frac {\left (7 (7 A-17 B+33 C) \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)}\right ) \int \cos ^{\frac {5}{2}}(c+d x) \, dx}{12 a^3}-\frac {\left ((13 A-33 B+63 C) \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)}\right ) \int \cos ^{\frac {3}{2}}(c+d x) \, dx}{4 a^3}\\ &=-\frac {(A-B+C) \sin (c+d x)}{5 d (a+a \cos (c+d x))^3 \sec ^{\frac {9}{2}}(c+d x)}-\frac {(2 A-7 B+12 C) \sin (c+d x)}{15 a d (a+a \cos (c+d x))^2 \sec ^{\frac {7}{2}}(c+d x)}-\frac {(13 A-33 B+63 C) \sin (c+d x)}{10 d \left (a^3+a^3 \cos (c+d x)\right ) \sec ^{\frac {5}{2}}(c+d x)}+\frac {7 (7 A-17 B+33 C) \sin (c+d x)}{30 a^3 d \sec ^{\frac {3}{2}}(c+d x)}-\frac {(13 A-33 B+63 C) \sin (c+d x)}{6 a^3 d \sqrt {\sec (c+d x)}}+\frac {\left (7 (7 A-17 B+33 C) \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)}\right ) \int \sqrt {\cos (c+d x)} \, dx}{20 a^3}-\frac {\left ((13 A-33 B+63 C) \sqrt {\cos (c+d x)} \sqrt {\sec (c+d x)}\right ) \int \frac {1}{\sqrt {\cos (c+d x)}} \, dx}{12 a^3}\\ &=\frac {7 (7 A-17 B+33 C) \sqrt {\cos (c+d x)} E\left (\left .\frac {1}{2} (c+d x)\right |2\right ) \sqrt {\sec (c+d x)}}{10 a^3 d}-\frac {(13 A-33 B+63 C) \sqrt {\cos (c+d x)} F\left (\left .\frac {1}{2} (c+d x)\right |2\right ) \sqrt {\sec (c+d x)}}{6 a^3 d}-\frac {(A-B+C) \sin (c+d x)}{5 d (a+a \cos (c+d x))^3 \sec ^{\frac {9}{2}}(c+d x)}-\frac {(2 A-7 B+12 C) \sin (c+d x)}{15 a d (a+a \cos (c+d x))^2 \sec ^{\frac {7}{2}}(c+d x)}-\frac {(13 A-33 B+63 C) \sin (c+d x)}{10 d \left (a^3+a^3 \cos (c+d x)\right ) \sec ^{\frac {5}{2}}(c+d x)}+\frac {7 (7 A-17 B+33 C) \sin (c+d x)}{30 a^3 d \sec ^{\frac {3}{2}}(c+d x)}-\frac {(13 A-33 B+63 C) \sin (c+d x)}{6 a^3 d \sqrt {\sec (c+d x)}}\\ \end {align*}
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Mathematica [A] time = 3.05, size = 229, normalized size = 0.73 \[ \frac {2 \cos ^6\left (\frac {1}{2} (c+d x)\right ) \sqrt {\sec (c+d x)} \left (-10 (13 A-33 B+63 C) \sqrt {\cos (c+d x)} F\left (\left .\frac {1}{2} (c+d x)\right |2\right )+42 (7 A-17 B+33 C) \sqrt {\cos (c+d x)} E\left (\left .\frac {1}{2} (c+d x)\right |2\right )+\frac {1}{8} \left (\sin \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {3}{2} (c+d x)\right )\right ) \sec ^5\left (\frac {1}{2} (c+d x)\right ) (2 (146 A-391 B+732 C) \cos (c+d x)+3 (29 A-79 B+143 C) \cos (2 (c+d x))+217 A-10 B \cos (3 (c+d x))-567 B+12 C \cos (3 (c+d x))-3 C \cos (4 (c+d x))+1062 C)\right )}{15 a^3 d (\cos (c+d x)+1)^3} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.55, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {C \cos \left (d x + c\right )^{2} + B \cos \left (d x + c\right ) + A}{{\left (a^{3} \cos \left (d x + c\right )^{3} + 3 \, a^{3} \cos \left (d x + c\right )^{2} + 3 \, a^{3} \cos \left (d x + c\right ) + a^{3}\right )} \sec \left (d x + c\right )^{\frac {7}{2}}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {C \cos \left (d x + c\right )^{2} + B \cos \left (d x + c\right ) + A}{{\left (a \cos \left (d x + c\right ) + a\right )}^{3} \sec \left (d x + c\right )^{\frac {7}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 3.13, size = 666, normalized size = 2.13 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {C \cos \left (d x + c\right )^{2} + B \cos \left (d x + c\right ) + A}{{\left (a \cos \left (d x + c\right ) + a\right )}^{3} \sec \left (d x + c\right )^{\frac {7}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {C\,{\cos \left (c+d\,x\right )}^2+B\,\cos \left (c+d\,x\right )+A}{{\left (\frac {1}{\cos \left (c+d\,x\right )}\right )}^{7/2}\,{\left (a+a\,\cos \left (c+d\,x\right )\right )}^3} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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